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      Entretien pour Associate Software Engineer

      24 janv. 2022
      Candidat à l'entretien anonyme
      Bhīmavaram
      Aucune offre
      Expérience neutre
      Entretien moyen

      Candidature

      J'ai postulé via un établissement d'enseignement supérieur ou universitaire. Le processus a pris 2 semaines. J'ai passé un entretien chez Zessta Software Services (Bhīmavaram) en nov. 2021

      Entretien

      First there will be a written test and after qualifying in that there will be a technical round in technical round asked about the technologies mentioned in the resume and abou project

      Autres retours d’entretien d’embauche pour un poste comme Associate Software Engineer chez Zessta Software Services

      Entretien pour Associate Software Engineer

      2 déc. 2024
      Candidat à l'entretien anonyme
      Hyderâbâd
      Aucune offre
      Expérience positive
      Entretien moyen

      Candidature

      J'ai postulé via un établissement d'enseignement supérieur ou universitaire. J'ai passé un entretien chez Zessta Software Services (Hyderâbâd) en déc. 2024

      Entretien

      on campus , 3 round , first round 3 hours on zessta s own test platform ,online test (aptitude 10% weightage + coding 3 question 90% weightage+ logical 10%) , 2nd round technical , 3rd round hr

      Questions d'entretien [4]

      Question 1

      You are tasked with building a file deduplication system that can efficiently handle large sets of files and identify duplicate files based on their contents, even if their names differ. Your system should perform the following tasks: Input: You are given a list of files, where each file has: A name (string) A file path (string) A file content (string representing the content of the file) Output: You need to output a set of file groups where each group contains the list of files that are duplicates of each other (i.e., they have the exact same content). The group should contain the file paths, but the files should be grouped regardless of their names. "/path/to/file1.txt, /path/to/file2.txt" If no files are found to be duplicates, the output should return the text: "No duplicates found" Optimization: Your solution must be optimized for: Time complexity: The algorithm should handle large numbers of files efficiently (e.g., handling 100,000+ files). Space complexity: The solution should use space efficiently while storing content and performing comparisons. Edge Cases: Empty Files: Handle cases where some files are empty. Large Files: Consider how to handle very large files efficiently, possibly using techniques like hashing. Multiple Duplicates: A file can appear multiple times, and all appearances should be grouped together. Mixed file paths: Files may appear under different paths but could have identical content.
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      Question 2

      Optimal Denomination Count Write a function that takes an integer representing a valid withdrawal amount and returns a string showing the optimal count of each denomination (₹2000, ₹500 ₹100) to dispense. The output should use the largest denominations possible to minimize the total number of notes. Example 1: Input: 900 Output: 500: 1, 100:4 Example 2: Input: 2800 Output: 2000: 1, 500: 1, 100: 3 }
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      Question 3

      Find the longest distance between coordinates You are given two sets of coordinates: 1. A starting point represented by the array [x1, y1]. 2. A destination point array with multiple coordinate pairs, such as [x2, y2, x3,y3, ..., xn, yn]. Your task is to find the destination point that has the longest distance from the starting point using the distance formula: [d=√(x2-21)2 + (y2 - y1)2] Where: ■(x1, y1) is the starting point, (x2, y2), (x3, y3), (x4, y4) are the destination points. Special Conditions: - If the starting point and any destination point are the same, the distance is 0. In this case, the output should be [-1, -1]. - If there are no destination coordinates provided, the output should be [-1, -1]. - If two or more destination points have the same maximum distance, the output should be [-1, -1]. Write a function findLongestDistancePoint that takes the starting coordinates and an array of destination coordinates, and returns the destination point that is farthest from the starting point, considering the special conditions. Input: - A coordinate array [x1, y1] representing the starting point. A coordinate array [x2, y2, x3, y3, xn, yn] representing multiple destination coordinates. Output: - The destination point (as an array [x, y]) that is farthest from the starting point, or [-1, -1] if the conditions are met. Example 1: Input: Starting Point: [2, 2] Destination Points: [2, 2, 2, 2] Output: [-1, -1] Explanation: Since the destination points are the same as the starting point, the distance is 8. As per the condition, the output is [-1, -1]. Example 2: Input: Starting Point: [0, 5] Destination Points: [1, 2, 3, 4, 5] Output: [-1, -1] Explanation: There are no coordinates representing valid destination points (pairs of coordinates are missing), so the output is [-1, -1]. Example 3: Input: Starting Point: [1, 2] Destination Points: [1, 2, 3, 4, 5, 6] Output: [5, 6] Explanation: The distance to each destination point is calculated: Distance to [1, 2]: d = 0 (same point). Distance to [3, 4]: d ≈ 2.83. Distance to [5, 6]: d≈ 5.39. The farthest point is [5, 6], so it is returned.
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      Question 4

      aptitude percentage basic level questions
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      2