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      Entretien pour Software Engineer(Internship)

      1 sept. 2024
      Candidat à l'entretien anonyme
      Hyderâbâd
      Aucune offre
      Expérience neutre
      Entretien moyen

      Candidature

      J'ai postulé via un établissement d'enseignement supérieur ou universitaire. Le processus a pris 2 jours. J'ai passé un entretien chez HugoSave (Hyderâbâd) en août 2024

      Entretien

      2 coding questions were asked each by a different person(for 30 min each). first question was easy and the second question was medium. just after that hr interview happened. common questions were asked in hr round like: what type of co-workers do you want? are you willing to relocate? what do you do apart from school?

      Questions d'entretien [1]

      Question 1

      You are given n tests numbered from 1, 2, 3.... N. Each test passes individually, but there are two tests which when ran together fails. You can call a function testSuite() and pass any number of test as you want. For example : Given N = 5, 1, 2, 3, 4, 5 Lets say 1 and 4 are failing tests. If you ran testSuite([1, 2, 3, 4, 5]) -> fail If you ran testSuite([1, 2, 3]) -> pass If you ran testSuite([1, 2, 4]) -> fail Likewise, testSuite([1, 4]) -> fail Can you write a algorithm (better than O(N^2) ofcourse) to find the failing tests? 2nd question: You are given a 0-indexed integer array nums and an integer k. A subarray is called equal if all of its elements are equal. Note that the empty subarray is an equal subarray. Return the length of the longest possible equal subarray after deleting at most k elements from nums. A subarray is a contiguous, possibly empty sequence of elements within an array. Example 1: Input: nums = [1,3,2,3,1,3], k = 3 Output: 3 Explanation: It's optimal to delete the elements at index 2 and index 4. After deleting them, nums becomes equal to [1, 3, 3, 3]. The longest equal subarray starts at i = 1 and ends at j = 3 with length equal to 3. It can be proven that no longer equal subarrays can be created. Example 2: Input: nums = [1,1,2,2,1,1], k = 2 Output: 4 Explanation: It's optimal to delete the elements at index 2 and index 3. After deleting them, nums becomes equal to [1, 1, 1, 1]. The array itself is an equal subarray, so the answer is 4. It can be proven that no longer equal subarrays can be created.
      1 réponse

      Autres retours d’entretien d’embauche pour un poste comme Software Engineer(Internship) chez HugoSave

      Entretien pour Software Engineer(Internship)

      31 juil. 2025
      Candidat à l'entretien anonyme
      Hyderâbâd
      Aucune offre
      Expérience positive
      Entretien moyen

      Candidature

      J'ai postulé via une autre source. Le processus a pris 1 jour. J'ai passé un entretien chez HugoSave (Hyderâbâd) en juin 2025

      Entretien

      There were 2 rounds; both were DSA focused. They were very user-friendly and will encourage you during the interview process. Both the questions from the Striver DSA sheet and from easy to medium. level.

      Questions d'entretien [1]

      Question 1

      first question they ask about sorting algorithms and complexity related to that then they asked me about merge sorting and said me to write the full code. In second round they asked me medium level questions from strings
      Répondre à cette question

      Entretien pour Software Engineer(Internship)

      24 oct. 2024
      Candidat à l'entretien anonyme
      Hyderâbâd
      Aucune offre
      Expérience positive
      Entretien moyen

      Candidature

      J'ai postulé via un établissement d'enseignement supérieur ou universitaire. Le processus a pris 1 semaine. J'ai passé un entretien chez HugoSave (Hyderâbâd) en août 2024

      Entretien

      It was on-campus opportunity. Held in the month of August. First round was a test, 2 medium to hard level questions. Based on the code written the platform checks for any plagiarism, and out of around 40 students 2 were selected. And the next rounds were 2 technical rounds and a HR round. Both were based on medium level Leetcode questions, but a modified version and a greedy problem, followed by Projects discussion. Both rounds of half an hour each. I was not able to explain the optimal approach properly, so didn't have an HR round.

      Questions d'entretien [1]

      Question 1

      3 Sum closest question and all approaches, and other questions based on Greedy and Binary Search
      Répondre à cette question