Find the second smallest integer in an array. Do not worry about duplicates.

Question

Utilisateur anonyme · Accepted Answer

I sorted the array and returned the second element.

Utilisateur anonyme · Answer

You need to use Hoare partition

Utilisateur anonyme · Answer

Do not sort the array that’ll give you O(nlogn) runtime, you can do this in O(n) runtime with one pass through the array

Alex Palomo · Answer

void secondSmallest(int arr[], int arr_size)
{
    int i, first, second;

    first = second = arr[0];
    for (i = 0; i < arr_size ; i ++)
    {
        if (arr[i] < first)
        {
            second = first;
            first = arr[i];
        }
        else if (arr[i] < second)
            second = arr[i];
    }
    printf("The second smallest element is %d", second);
}

Anonymous · Answer

def second_smallest_num(arr):
    new_arr = {"smallest": arr[0], "second": arr[1]}
    pivot = arr[0]
    for i in arr:
        if i  new_arr["smallest"]:
                new_arr["second"] = i
    print new_arr

    
arr = [200,-100,-3,-2,0,4,-3,-1]
second_smallest_num(arr)

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