code a function that takes 2 parameters and an algorithm, print out all the numbers between the 2 parameters that completes the algorithm

Question

Sid · Accepted Answer

void foo(int a, int b, Func algo)
{
  for(int i =a; i < b;i++)  
 {
   if(algo(i))
   {
     Console.WriteLine(i);
   }
 }
}

Sid · Answer

The Signature of third parameter is not completely visible , dont know why. Its void foo(int a, int b, Func algo)

Utilisateur anonyme · Answer

The Signature of third parameter is not completely visible ,  "Func algo"

Alejandro · Answer

We know that Function passes in 2  template types T and R. T extends Number/Integer and since the number is passed to the algorithm to check for completeness. If you define complete to be true false then R is Boolean or extends Boolean. If not then you have to ask for a definition of complete. Assuming completeeans boolean true then:

void f(int a, int b, Function func) {
  int start = a

Alejandro · Answer

We know that Function passes in 2  template types T and R. T extends Number/Integer and since the number is passed to the algorithm to check for completeness. If you define complete to be true/false then R is Boolean or extends Boolean. If not then you have to ask for a definition complete.

void f(int a, int b, Function func) {
  int start = a

Ala' Alnajjar · Answer

void Test(int a,int b, Func algo){
		for(var i=a;i

Spirus · Answer

@FunctionalInterface
public interface Func {
	int calculate(Integer a, Integer b); 
}

public class NoName {
public static void main(String[] args) {
                Func func = (a,b) -> a+b;		
		System.out.println(func(1, 2, func));
}

static int func(final int a, final int b, Func func) {
		return func.calculate(a, b);
		
	}
}

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