Check if 2 strings are palindrome?

Question

ab · Accepted Answer

char *str = "civic";

char* begin = str;
char* end = str + strlen(str) - 1;

int is_palindrome = 1;

while ( begin < end ) {
 
  if ( to_upper(*begin) == to_upper(*end))  
    continue;
 else 
   {
     is_palindrome = 0; break;
   }
}

Utilisateur anonyme · Answer

I provided algorithm with O(n2) complexity. They he asked for optimizing it for speed. I gave another algorithm with O(nlogn) that involves mergesort of individual strings and then one-to-one comparison. Everyone can have their own algorithms and he wanted me provide algorithm as he had in his mind... he kept asking for O(n) solution that i could not completely provide in given amount of time...

Siva · Answer

Just take reverse of any one of the strings and compare the rest and the string which is reversed.
   Theta(n) + Theta(n) = 2 * Theta(n) = Theta(n)

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